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Projectile Motion

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Projectile Motion

Post Number: #1  Postby Jessica » October 18th, 2011, 10:18 pm

Trajectory: the path of an object undergoing projectory motion

3 types:
  • horizontal launch
  • launching and landing at same height
  • launching and landing at different heights

Horizontal Launch Problem Solving Strategy

1. Separate the x and y variables:

x

V[sub]x[/sub] = ?
Δx = ?
Δt = ?
y
a[sub]g[/sub] = -9.80 m/s2
V[sub]1y[/sub] = 0
Δy = ?
Δt = ?
V[sub]2y[/sub] = ?


Δt for both x and y are the same


2. Use with the x column and/or the kinematic equations w/ the y column




Launching and Landing at Same Height Problem Solving Strategy

1. Calculate the x and y components of the initial velocity.

2.
x

V[sub]x[/sub] = ?
Δx = ?
Δt = ?
y
a[sub]g[/sub] = -9.80 m/s2
V[sub]1y[/sub] = ?
Δy = 0 *if position 2 at same height as launch
V[sub]2y[/sub] = 0 *if position 2 at highest point


3. Analyze x direction using and/or the y direction using the kinematic equations.
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Re: Projectile Motion

Post Number: #2  Postby Jessica » September 23rd, 2013, 10:51 pm

If air resistance is neglected, the motion of a projectile is the superposition of two independent motions:
  • a horizontal motion with constant velocity (equal to initial horizontal velocity, v[sub]0x[/sub] = v[sub]0[/sub]cosθ[sub]0[/sub];
  • a vertical motion with constant acceleration (−g) and initial vertical velocity v[sub]0y[/sub] = v[sub]0[/sub]sinθ[sub]0[/sub]


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